Write the SI unit of the physical quantity having following dimensional formula
$[M^{0} L^{2} T^{- 2} K^{- 1}]$ .

m {k g}^{2} K^{- 1}

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m^{2} {k g}^{2} T^{- 1}

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m^{2} s^{- 2} K^{- 1}

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m^{2} {k g}^{2} K^{- 1}

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Solution

The correct option is D $m^{2} s^{- 2} K^{- 1}$
SI unit of $M$ is $k g$ , that of $L$ is $m$ , $T$ is $s$ and temperature (K) is $K$ .

So, SI unit of $[M^{0} L^{2} T^{- 2} K^{- 1}]$ is $m^{2} s^{- 2} K^{- 1}$ .

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