Question

Write the smallest digit and the largest digit in the blank for the given number so that the number formed is divisibly by 3:
4765_2 (4 Marks)

Answer 1

We know that a number is divisible by 3 if the sum of all digits is divisible by 3.

4 + 7 + 6 + 5 + 2 = 24, which is divisible by 3.
(1 Marks)

Therefore, Smallest digit: 0 (0 is the smallest digit which will not change the sum as the sum is already divisible by 3)
So, the number formed is 476502.
Sum of the digits = 4 + 7 + 6 + 5 + 0 + 2 = 24 [24 is divisible by 3]
(1.5 Mark)

Also, Largest digit: 9
So, the number formed is 476592.
Sum of the digits = = 4 + 7 + 6 + 5 + 9 + 2 = 33 [33 is divisible by 3]
(1.5 Mark)