Question

Write the structural formula for 4-iodononane.

Answer 1

Given the IUPAC name is 4-iodononane.
Since the root word is non, there will be nine carbons in the main carbon chain.
The primary suffix is -ane and all the carbon atoms linked with only single bonds in the main carbon. The prefix is iodo, so the group is iodine (-I).
The position of the iodine is on the fourth carbon (4-iodo).
Therefore the structural formula is ${\text{CH}}_3{\text{CH}}_2{\text{CH}}_2{\text{CH}}_2{\text{CH}}_2{\text{CHICH}}_2{\text{CH}}_2{\text{CH}}_3$.