Ethanol is warmed with ethanoic acid to form ethyl acetate in the presence of concentrated H2SO4.
A
Esterification reaction
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B
Neutralisation reaction
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C
Decomposition reaction
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D
Double displacement reaction
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Solution
The correct option is A Esterification reaction Reaction of ethanol with warm ethanoic acid to form ethyl acetate(an ester) and water can be written as: C2H5OH+CH3COOHH+→CH3COOC2H5+H2O (ethanol) (ethanoic acid) (ester) Above reaction is an esterification reaction as an alcohol and an acid are combined to formed an ester.