Write the value of $(^i \times^j) \cdot^k +^i \cdot^j .$

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Solution

Since $(^i \times^j) =^k$

Now consider $(^i \times^j) \cdot^k +^i \cdot^j$ as shown below:

$(^i \times^j) \cdot^k +^i \cdot^j =^k \cdot^k +^i \cdot^j = 1 + 0 = 1$

Hence, $(^i \times^j) \cdot^k +^i \cdot^j = 1$ .

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Similar questions

^i \cdot (^j \times^k) +^j \cdot (^k \times^i) +^k \cdot (^j \times^i)

Choose the correct answer
The value of $^i . (^j \times^k) +^j . (^k \times^i) +^k (^i \times^j)$ is
a) Zero
b) - 1
c) 1
d) 3

(^k \times^i) \cdot^j +^i \cdot^k

(^k \times^j) \cdot^i +^j \cdot^k .

^i,^j,^k

^i \cdot (^j \times^k) +^j \cdot (^i \times^k) +^k \cdot (^i \times^j)

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