Question

Write two tests to demonstrate Ethanoic acid is acidic in nature?

Answer 1

Part 1:

1. The reaction of Ethanoic acid with Sodium hydrogen carbonate results in the evolution of Carbon dioxide gas.
2. The reaction suggests that the Hydrogen present in $\mathbf{-}\mathbf{COOH}$ a group of Ethanoic acid is acidic in nature.
3. The reaction is represented as follows:

$\underset{\mathbf{Sodium}\mathbf{}\mathbf{hydrogen}\mathbf{}\mathbf{carbonate}}{{\mathbf{NaHCO}}_{\mathbf{3}}\mathbf{}\mathbf{\left(}\mathbf{aq}\mathbf{\right)}}\mathbf{+}\mathbf{}\underset{\mathbf{Ethanoic}\mathbf{}\mathbf{acid}}{{\mathbf{CH}}_{\mathbf{3}}\mathbf{COOH}\mathbf{}\mathbf{(}\mathbf{aq}}\mathbf{)}\mathbf{}\mathbf{\to }\mathbf{}\underset{\mathbf{Sodium}\mathbf{}\mathbf{acetate}}{{\mathbf{CH}}_{\mathbf{3}}\mathbf{COONa}\mathbf{}\mathbf{\left(}\mathbf{aq}\mathbf{\right)}}\mathbf{}\mathbf{+}\mathbf{}{\mathbf{H}}_{\mathbf{2}}\mathbf{O}\mathbf{}\mathbf{(}\mathbf{l}\mathbf{)}\mathbf{}\mathbf{+}{\mathbf{CO}}_{\mathbf{2}}\mathbf{}\mathbf{(}\mathbf{g}\mathbf{)}$

Part 2:

1. The reaction of Ethanoic acid with Sodium carbonate results in the evolution of Carbon dioxide gas.
2. The reaction suggests that the Hydrogen present in $\mathbf{-}\mathbf{COOH}$ a group of Ethanoic acid is acidic in nature.
3. The reaction is represented as follows:

$\underset{\mathbf{Sodium}\mathbf{}\mathbf{carbonate}}{{\mathbf{Na}}_{\mathbf{2}}{\mathbf{CO}}_{\mathbf{3}}\mathbf{}\mathbf{\left(}\mathbf{aq}\mathbf{\right)}}\mathbf{}\mathbf{+}\mathbf{}\underset{\mathbf{Ethanoic}\mathbf{}\mathbf{acid}}{\mathbf{2}\mathbf{}{\mathbf{CH}}_{\mathbf{3}}\mathbf{COOH}\mathbf{}\mathbf{\left(}\mathbf{aq}\mathbf{\right)}}\mathbf{}\mathbf{\to }\mathbf{}\underset{\mathbf{Sodium}\mathbf{}\mathit{E}\mathit{t}\mathit{h}\mathit{a}\mathit{n}\mathit{o}\mathit{a}\mathit{t}\mathit{e}}{\mathbf{2}\mathbf{}{\mathbf{CH}}_{\mathbf{3}}\mathbf{COONa}\mathbf{}\mathbf{\left(}\mathbf{aq}\mathbf{\right)}\mathbf{}}\mathbf{+}\mathbf{}{\mathbf{H}}_{\mathbf{2}}\mathbf{O}\mathbf{}\mathbf{\left(}\mathbf{l}\mathbf{\right)}\mathbf{}\mathbf{+}\underset{\mathbf{Carbon}\mathbf{}\mathbf{dioxide}}{\mathbf{}{\mathbf{CO}}_{\mathbf{2}}\mathbf{}\mathbf{\left(}\mathbf{g}\mathbf{\right)}}$