Written:

Construct a triangle PQR, in which PQ = QR = RP = 6 cm.

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Solution

Construction of ΔPQR, where PQ = QR = RP = 6 cm.

Steps of construction:

(i) Draw PQ = 6 cm.

(ii) Using the compass, with P and Q as centers and radii as 6 cm, draw arcs which cut each other at point R,

Here, triangle PQR is the required triangle.

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Similar questions

Written:

Construct a triangle PQR, in which PQ = 6.7 cm, QR = PR = 5.4 cm.

P Q R

Q R = 6 c m

∠ Q = 60^{o}

P Q - P O = 2 c m

Construct a triangle PQR in which QR = 6 cm, ∠Q = 60° and PR − PQ = 2 cm

△ P Q R, P Q = 5 c m, Q R = 6 c m

R P = 8.2 c m

△ P Q R, P Q = 5 c m, Q R = 6 c m

R P = 8.2 c m

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