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Question

|x2+2x8|+x2=0

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Solution

(x2+2x8)+(x2)=0
(x2+4x2x8)+(x2)=0
[x(x+4)2(x+4)]+(x2)=0
[(x2)(x+4)]+(x2)=0
[x2][1+(x+4)]=0
x=2,x=5

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