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Polynomial and Its General Form

x 2 - 4 a x ...

Question

$x^{2} - 4 a x + 4 a^{2} - b^{2} = 0$

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Solution

$\begin{matrix} x^{2} - 4 a x + 4 a^{2} - b^{2} = 0 [x^{2} - 2 \times x \times 2 a + {(2 a)}^{2}] = b^{2} {(x - 2 a)}^{2} = b^{2} ∴ x - 2 a = b o r x - 2 a = - b ∴ x = 2 a + b o r x = 2 a - b \end{matrix}$

Hence, this is the answer.

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