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Question

x^2+4abx-(a^2-b^2)^2

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Solution

x2 - 4abx - (a2 - b2)2
= x2 - 4abx + 4a2b2- 4a2b2 - (a2 - b2)2
= (x)2 - 2*x*2ab + (2ab)2 - 4a2b2 - (a4 + b4 - 2a2b2)
= (x - 2ab)2 - 4a2b2 - a4 - b4 + 2a2b2
= (x - 2ab)2 - a4 - b4 - 2a2b2
= (x - 2ab)2 - (a4 + b4 + 2a2b2)
= (x - 2ab)2 - [(a2)2 + (b2)2 + 2*a2*b2]
= (x - 2ab)2 - (a2 + b2)2
= [(x - 2ab) + (a2 + b2)] * [(x - 2ab) - (a2 + b2)]
= [x - 2ab + a2 + b2] * [x - 2ab - a2 + b2]
= [x + a2 + b2 - 2ab] * [x - (a2 + b2 + 2ab]
= [x + (a - b)2] * [x - (a + b)2]

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