x2- 7x + 12 = 0
y2 + y - 12 = 0
if x y
if x = y
On solving the equations, x = 4, 3 y = -4, 3
So, x≥ y
x2−7x+12=0
y2+y−12=0
x2 + x - 20 = 0
y2 - y -30 = 0
Find the equation of family of circles through the intersection of x2 + y2 − 6x + 2y + 4 = 0 and x2 + y2 + 2x − 4y − 6 = 0 whose center lies on y = x.