(x + 2) is a factor of $x^{4}$ - 16.

True

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False

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Solution

The correct option is A
True

$x^{4}$ - 16 = ( $x^{2}$ - 4) ( $x^{2}$ + 4)........... [using $a^{2} - b^{2}$ = (a + b)(a - b)]

( $x^{2}$ - 4) is further factorable using the same formula.

So we get, ( $x^{2}$ - 4) = (x + 2)(x - 2)

This shows that, (x + 2) is a factor of $x^{4}$ - 16

Suggest Corrections

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