$x + 2 y + 3 z = 6$
$2 x + 4 y + z = 17$
$3 x + 2 y + 9 z = 2$ .
Solve by Crammer's rule

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Solution

$D = - 20, D_{1} = - 20, D_{2} = - 80, D_{3} = 20$

$1, 4, - 1$

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Similar questions

x + 2 y + 3 z = 6, 2 x + 4 y + z = 17, 3 x + 2 y + 9 z = 2

x + y + z

x + y + z = 1

2 x + 2 y + 3 z = 6

x + 4 y + 9 z = 3

a x + b y + c z = k

a^{2} x + b^{2} y + c^{2} z = k^{2}

a^{3} x + b^{3} y + c^{3} z = k^{3}

x + y + z = 1, 2 x + 2 y + 3 z = 6, x + 4 y + 9 z = 3

x + y + z = 1

a x + b y + c z = k

a^{2} x + b^{2} y + c^{2} z = k^{2}

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