Question 90 (x)

Factorise the following, using the identity, $a^{2} - 2 a b + b^{2} = (a - b)^{2}$ .

$\frac{x^{2}}{4} - 2 x + 4$

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Solution

We have,
$\frac{x^{2}}{4} - 2 x + 4 = {(\frac{x}{2})}^{2} - 2. \frac{x}{2} .2 + 2^{2} = {(\frac{x}{2} - 2)}^{2} = (\frac{x}{2} - 2) (\frac{x}{2} - 2)$

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