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Stoichiometric Calculations

X g of Ca [...

Question

$X g$ of $C a$ [atomic mass $= 40$ ] dissolves completely in concentrated $H C l$ solution to produce $5.04 L$ of $H_{2}$ gas at STP. The value of $X$ is closest to:

4.5

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8.1

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9.0

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16.2

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Solution

The correct option is D $9.0$
$C a + 2 H C l \to C a C l_{2} + H_{2}$

1 mole of $C a$ produces $22.4 l$ of $H_{2}$

It means $22.4 l$ of $H_{2}$ is produced by $40 g$ of $C a$ .

So $5.04 l$ is produced by $= \frac{40 \times 5.04}{22.4} = 9 g$ of $C a$ .

Hence, option C is correct.

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X g of Ca [atomic mass =40] dissolves completely in concentrated HCl solution to produce 5.04 L of H2 gas at STP. The value of X is closest to:

The correct option is D 9.0Ca+2HCl→CaCl2+H21 mole of Ca produces 22.4 l of H2 It means 22.4 l of H2 is produced by 40g of Ca.So 5.04 l is produced by =40×5.0422.4=9 g of Ca.Hence, option C is correct.

$X g$ of $C a$ [atomic mass $= 40$ ] dissolves completely in concentrated $H C l$ solution to produce $5.04 L$ of $H_{2}$ gas at STP. The value of $X$ is closest to:

The correct option is D $9.0$
$C a + 2 H C l \to C a C l_{2} + H_{2}$

1 mole of $C a$ produces $22.4 l$ of $H_{2}$

It means $22.4 l$ of $H_{2}$ is produced by $40 g$ of $C a$ .

So $5.04 l$ is produced by $= \frac{40 \times 5.04}{22.4} = 9 g$ of $C a$ .

Hence, option C is correct.