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Heat of Reaction

X g of KM nO ...

Question

X g of $K M n O_{4}$ on being treated with $K I$ in acid solution liberates just sufficient $I_{2}$ to react with 50 ml of 0.1 M hypo solution.
$N a_{2} S_{2} O_{3} + I_{2} \to N a_{2} S_{4} O_{6} + 2 N a I$
Find the value of X. (The molecular weight of $K M n O_{4} = 158 g m o l^{- 1}$ )
.

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Solution

According to question, meq. of $K M n O_{4}$ = meq. of $I_{2}$ = meq. of hypo = $50 \times 0.1 \times 1 = 5$
$\frac{X}{\frac{158}{5}} \times 10^{- 3}$ = 5
$X = 0.158 g$
Thus, mass of $K M n O_{4}$ is 0.158 g

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