X has twice as much money as that of y and y has 50 % more money than that of Z . If the average money of all of them is Rs 110, then the money which X Has
A
Rs 55
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B
Rs 60
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C
Rs 90
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D
Rs 180
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Solution
The correct option is C Rs 180 Let Z have Rs X. Then, Y has 150% of Rs X = Rs 150X100=Rs3X2 X has 2 x Rs 3X2 = Rs 3X Given, X+3X2+3X3=10 ⇒2X+3X+6X2=330 ⇒11X=660⇒x=60 ∴ Amount that X has = 3 x 60 = Rs 180