X-ray of wavelength $λ = 2 o A$ is emitted from the target metal. The potential difference applied across the cathode and the metal target is?

6200

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2000

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7000

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3500

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Solution

The correct option is A $6200$ V
Energy of X-ray emitted $E = \frac{h c}{λ} = \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{2 \times 10^{- 10}}$
$= 9.9 \times 10^{- 16}$ J
$= 6200$ eV ( $∵ 1 e V = 1.6 \times 10^{- 19} J$ )
$\Rightarrow$ Potential difference $= 6200$ V.

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X-ray of wavelength λ=2oA is emitted from the target metal. The potential difference applied across the cathode and the metal target is?

The correct option is A 6200VEnergy of X-ray emitted E=hcλ=6.6×10−34×3×1082×10−10=9.9×10−16J=6200eV (∵1eV=1.6×10−19J)⇒ Potential difference =6200V.

X-ray of wavelength $λ = 2 o A$ is emitted from the target metal. The potential difference applied across the cathode and the metal target is?

The correct option is A $6200$ V
Energy of X-ray emitted $E = \frac{h c}{λ} = \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{2 \times 10^{- 10}}$
$= 9.9 \times 10^{- 16}$ J
$= 6200$ eV ( $∵ 1 e V = 1.6 \times 10^{- 19} J$ )
$\Rightarrow$ Potential difference $= 6200$ V.