$x (x^{2} + x + 1)$ and find its value for $x = 2$ .

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Solution

We have,
$x (x^{2} + x + 1)$

Since, $x = 2$

So,
$\Rightarrow 2 (2^{2} + 2 + 1)$

$\Rightarrow 2 (4 + 3)$

$\Rightarrow 2 (7)$

$\Rightarrow 14$

Hence, this is the answer.

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