$x + x^{'} y =$

x

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y

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x - y

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x + y

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Solution

The correct option is D $x + y$
$x + x^{^{'}} y = x (1 + y) + x^{^{'}} y . . . [1 + y = 1] = x + x y + x^{^{'}} y = x + y (x + x^{^{'}}) . . . [x + x^{^{'}} = 1] = x + y .1 = x + y$ .

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