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Question

(x) x3+y4=4; 5x6-y8=4

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Solution

x3+y4=4 4x+3y=48 ...(i) 5x6-y8=4 20x-3y=96 ...(ii) Multiplying eq (i) by 5, we get :20x+15y=240 ...(iii) Subtracting eq (ii) from (iii), we get : 20x+15y=240 20x-3y = 96 - + - 18y= 144 y=8Substituting y=8 in (i), we get: 4x+3×8=48 4x=24x=6Hence, x=6, y=8 is the solution of the given equations.

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