$X s t e p I - -- \to Y s t e p I I - --- \to Z$ is a complex reaction. Total order of reaction is 2 and step II is the slowest step. What is molecularity of step II?

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 1
In chemistry it is always true that a uni-molecular reaction is much slower than a bi molecular one. So, step II is unimolecular.

Suggest Corrections

Similar questions

For a complex reaction ......... .

(a) order of overall reaction is same as molecularity of the slowest step
(b) order of overall reaction is less than the molecularity of the slowest step
(c) order of overall reaction is greater than molecularity of the slowest step
(d) molecularity of the slowest step is never zero or non-integer

Q. In the conplex reactions is the molecularity and order same of the slowest step?

Q. Assertion :Complex reaction takes place in different steps and the slowest step determines the rate of reaction. Reason: Order and molecularity of a reaction are always equal.

In any unimolecular reaction ......... .
(a) only one reacting species is involved in the rate determining step
(b) the order and the molecularity of slowest step are equalto one
(c) the molecularity of the reaction is one and order is zero
(d) both molecularity and order of the reaction are one

Q. Assertion :Molecularity greater than three is not observed. Reason: The overall molecularity of a complex reaction is equal to molecularity of the slowest step.

Join BYJU'S Learning Program

Xstep I−−−→Ystep II−−−−→Z is a complex reaction. Total order of reaction is 2 and step II is the slowest step. What is molecularity of step II?

The correct option is A 1In chemistry it is always true that a uni-molecular reaction is much slower than a bi molecular one. So, step II is unimolecular.

$X s t e p I - -- \to Y s t e p I I - --- \to Z$ is a complex reaction. Total order of reaction is 2 and step II is the slowest step. What is molecularity of step II?

The correct option is A 1
In chemistry it is always true that a uni-molecular reaction is much slower than a bi molecular one. So, step II is unimolecular.