The given system of equation is:
x − y = 3 .........(i)
3x − 2y = 10 ........(ii)
On multiplying (i) by 2, we get:
2x − 2y = 6 .......(iii)
On subtracting (iii) and (ii), we get:
x = 4
On substituting the value of x = 4 in (i), we get:
4 − y = 3
⇒ y = (4 − 3) = 1
Hence, the solution is x = 4 and y = 1.