$(x, y)$ and $(p, q)$ are two ordered pairs. Find the values of $x$ and $p$ , if $(3 x - 1, 9) = (11, p + 2)$

x = 4, p = 9

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x = 6, p = 7

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x = 4, p = 5

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x = 4, p = 7

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Solution

The correct option is D $x = 4, p = 7$
Given $(x, y) = (p, q)$
$(3 x - 1, 9) = (11, p + 2)$
By equating
$3 x - 1 = 11$
$3 x = 12$
$x = 4$
$9 = p + 2$
$p = 7$
So, the value of $x = 4, p = 7.$

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(x,y) and (p,q) are two ordered pairs. Find the values of x and p, if (3x−1,9)=(11,p+2)

The correct option is D x=4,p=7Given(x,y)=(p,q)(3x−1,9)=(11,p+2)By equating 3x−1=113x=12x=49=p+2p=7So, the value of x=4,p=7.

$(x, y)$ and $(p, q)$ are two ordered pairs. Find the values of $x$ and $p$ , if $(3 x - 1, 9) = (11, p + 2)$

The correct option is D $x = 4, p = 7$
Given $(x, y) = (p, q)$
$(3 x - 1, 9) = (11, p + 2)$
By equating
$3 x - 1 = 11$
$3 x = 12$
$x = 4$
$9 = p + 2$
$p = 7$
So, the value of $x = 4, p = 7.$