$x + y + z = 1, 2 x + 2 y + 3 z = 6, x + 4 y + 9 z = 3$ .

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Solution

Given equation
$x + y + z = 1 - - - - (1)$
$2 x + 2 y + 3 z = 5 - - - - (2)$
$x + 4 y + 9 z = 3 - - - - (3)$
$(2) - 2 \times (1) \Rightarrow \frac{2 x + 2 y + 3 z = 6 2 x + 2 y + 2 z = 2}{z = 4}$
$(2) - 2 \times (1) \Rightarrow \frac{x + 4 y + 9 z = 3 4 x + 4 y + 6 z = 12}{- 3 x + 3 z = - 9 - x + z = - 3 x = z + 3 = 7}$
$(1) \Rightarrow x + y + z = 1$
$7 + y + 4 = 1$
$y = - 10$
$∴ x = 7, y = - 10, z = 4$

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Similar questions

x + y + z = 1

2 x + 2 y + 3 z = 0

x + 4 y + 9 z = 3

x + y + z = 1

2 x + 2 y + 3 z = 6

x + 4 y + 9 z = 3

x + 2 y + 3 z = 1, 2 x + y + 3 z = 2, 5 x + 5 y + 9 z = 4

x + 2 y + 3 z = 6, 2 x + 4 y + z = 17, 3 x + 2 y + 9 z = 2

x + y + z

x + 2 y + 3 z = 1, 2 x + y + 3 z = 2

5 x + 5 y + 9 z = 4

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