Question

x = $y^2$If x < 625, then which of the following values 'y' can take?

• A. 27
• B. 24
• C. 16
• D. 19

Answer 1

Answer: (B), (C), (D)

The correct options are
B 24
C 16
D 19

Prime factorisation of 625 is
$625=5\times 5\times 5\times 5$

So, $\sqrt{625}=\sqrt{\underset{–}{5\times 5}\times \underset{–}{5\times 5}}$
$\Rightarrow \sqrt{625}=5\times 5=25$

Given: x < 625, which implies that 'y' can have values less than 25, as x = $y^2$.

Hence, the options, 24, 16 and 19 are the possible values for 'y' as they are less than 25.
But first option is 27 and 27 > 25. So, 'y' cannot take the value 27.