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Question
x³ + 3x² + 3x + 1 ÷ x + π
x³ + 3x² + 3x + 1 ÷ x + π
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Solution
Apply remainder theorem
=>x + π =0
=> x = - π
Replace x by – π we get
=>x3+3x2 + 3x + 1
=>(- π)3 + 3(-π)2 + 3(-π) + 1
=> - π3 + 3π2 - 3π + 1
Remainder is - π3 + 3π2 - 3π + 1
=>x + π =0
=> x = - π
Replace x by – π we get
=>x3+3x2 + 3x + 1
=>(- π)3 + 3(-π)2 + 3(-π) + 1
=> - π3 + 3π2 - 3π + 1
Remainder is - π3 + 3π2 - 3π + 1
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