$X e F_{4}$ reacts violently with water to give:

X e + O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

X e O_{3} + O_{2} + H F

No worries! We‘ve got your back. Try BYJU‘S free classes today!

X e + O_{2} + H F + X e O_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

X e O F_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $X e + O_{2} + H F + X e O_{3}$
$X e F_{4}$ reacts violently with water to give $X e, O_{2}, H F, X e O_{3}$

$6 X e F_{4} + 12 H_{2} O \to 2 X e O_{3} + 4 X e + 3 O_{2} + 24 H F$
Hence option C is correct.

Suggest Corrections

Similar questions

X e F_{4}

X e F_{2}

X e O_{3}, X e, H F, O_{2}

_{2}

N a < N O < X e = O_{2} . O_{2}

P t F_{6}

O_{2} [P t F_{6}] .

P t F_{6}

s p^{3} d

X e F_{2}, X e F_{4}, X e F_{6}, X e O F_{2}, X e O_{3}

O_{2}^{+} P t F_{6}^{-}

Join BYJU'S Learning Program