$X e F_{6}$ on hydrolysis produces :

X e O F_{4}

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X e O_{2} F_{2}

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X e O_{3}

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X e O_{2}

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Solution

The correct option is C $X e O_{3}$
Hydrolysis of $X e F_{6}$ with water gives $X e O_{3}$
$X e F_{6} + 3 H_{2} O \to X e O_{3} + 6 H F$
Partial hydrolysis of $X e F_{6}$ gives oxyflourides :
$X e F_{6} + 3 H_{2} O \to X e O F_{4} + 2 H F$
$X e F_{6} + 3 H_{2} O \to X e O_{2} F_{2} + 2 H F$

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