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Byju's Answer
Standard XII
Chemistry
Fluorides of Xenon
XeFn n = 2,4,...
Question
X
e
F
n
(
n
=
2
,
4
,
6
)
are oxidising agents and thus estimation of Xe salts can be determined by suitable methods.
X
e
F
4
+
4
K
I
⟶
X
e
+
2
I
2
+
4
K
F
Write the increasing order of oxidising power of xenon compounds ?
A
X
e
F
2
<
X
e
F
4
<
X
e
F
6
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B
X
e
F
2
<
X
e
F
6
<
X
e
F
4
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C
X
e
F
6
<
X
e
F
4
<
X
e
F
2
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D
X
e
F
6
=
X
e
F
4
=
X
e
F
2
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Solution
The correct option is
C
X
e
F
2
<
X
e
F
4
<
X
e
F
6
As the oxidation state of Xe increases, the compounds oxidizing power also increases.
So the increasing order of oxidizing power of xenon is-
X
e
F
2
<
X
e
F
4
<
X
e
F
6
+2 +4 +6
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Similar questions
Q.
Oxidising power of xenon fluorides increases in the order:
X
e
F
6
>
X
e
F
4
>
X
e
F
2
If true enter 1, else enter 0.
Q.
Hybridisation state of
X
e
in
X
e
F
2
,
X
e
F
4
, and
X
e
F
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respectively are:
Q.
The increasing
d
-character in hybridisation of
X
e
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X
e
F
2
,
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e
F
4
,
X
e
F
6
is
:
Q.
How are xenon fluorides
X
e
F
2
,
X
e
F
4
and
X
e
F
6
obtained?
Q.
In
X
e
F
2
,
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e
F
4
, and
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e
F
6
, the number of lone pairs on
X
e
, is__________.
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