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Byju's Answer
Standard IX
Mathematics
Taking Out Common Factors
Question 88x ...
Question
Question 88 (xv)
Factorise the following expression.
y
2
+
8
z
x
−
2
x
y
−
4
y
z
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Solution
We have,
y
2
+
8
z
x
−
2
x
y
−
4
y
z
=
y
2
−
2
x
y
+
8
z
x
−
4
y
z
=
y
(
y
−
2
x
)
−
4
z
(
y
−
2
x
)
=
(
y
−
2
x
)
(
y
−
4
z
)
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Similar questions
Q.
Question 88 (xv)
Factorise the following expression.
y
2
+
8
z
x
−
2
x
y
−
4
y
z
Q.
Simplify:
(
2
x
+
y
+
4
z
)
(
4
x
2
+
y
2
+
16
z
2
−
2
x
y
−
4
y
z
−
8
z
x
)
.
Q.
The expansion of (
x
−
y
+
2
z
)
2
is _______.
Q.
Evaluate:
2
x
2
+
y
2
+
8
z
2
−
2
√
2
x
y
+
4
√
2
y
z
−
8
z
x
Q.
When
4
y
z
+
9
z
x
−
4
y
and
−
3
x
z
+
5
x
−
2
x
y
are added, we get
4
y
z
+
6
x
z
−
2
x
y
−
4
y
+
5
x
.
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Taking Out Common Factors
Standard IX Mathematics
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