Y12- y6- y3- y - ym- then m -

y^12÷(y^6× y^3× y)=y^m x^a× x^b=x^a+b ∴ y^6× y^3× y=y^6+3+1=y^10 y^a÷ y^b=y^a b ∴ y^12÷ y^10=y^2 ∴ y^2=y^m m=2 ...

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Power Law

y12÷ y6× y3× ...

Question

$y^{12} \div (y^{6} \times y^{3} \times y)$ = $y^{m}$ , then m =.

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Solution

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