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Question

y=Acosnx+Bsinnx
Prove that d2ydx2+n2y=0.

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Solution

y=Acosnx+Bsinnx
dydx=An(sinnx)+Bn(cosnx)
d2ydx2=n2Acosnx+n2B(sinx)
=n2(Acosnx+Bsinnx)
d2ydx2+n2y=0

1237148_1103008_ans_3244a6d2bd7c43b8891438e881671138.jpg

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