Y-cos x - yn-dncos x-dxn then y4 y5 y6 y7 y8 y9 y10 y11 y12 -

The correct option is D 0 y_ 4 amp; y_ 5 amp; y_ 6 y_ 7 amp; y_ 8 amp; y_ 9 y_ 10 amp; y_ 11 amp; y_ 12 =sin x nbsp; ...

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Implicit Differentiation

y=cos x , yn=...

Question

$y = cos x, y_{n} = \frac{d^{n} (cos x)}{d x^{n}}$ then $∣ ∣ ∣ ∣ \begin{matrix} y_{4} & y_{5} & y_{6} y_{7} & y_{8} & y_{9} y_{10} & y_{11} & y_{12} \end{matrix} ∣ ∣ ∣ ∣$ =

0

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- cos x

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cos x

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sin x

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Solution

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Similar questions

y = cos x, y_{n} = \frac{d^{n} (cos x)}{d x^{n}}

∣ ∣ ∣ ∣ \begin{matrix} y_{4} & y_{5} & y_{6} y_{7} & y_{8} & y_{9} y_{10} & y_{11} & y_{12} \end{matrix} ∣ ∣ ∣ ∣ =

y = \frac{sin x}{1 + \frac{cos x}{1 + \frac{sin x}{1 + \frac{cos x}{1 + \frac{sin x}{1 + . . . . . \infty}}}}}

y^{'} (0)

y = {tan}^{- 1} (\frac{cos x - sin x}{cos x + sin x})

\frac{d y}{d x} =

y = \frac{cos x - sin x}{cos x + sin x}

\frac{d y}{d x} + y^{2} + 1 = 0

y = \sqrt{cos x + \sqrt{cos x + \sqrt{cos x + . . . . . . . \infty}}}

\frac{d y}{d x} = \frac{- sin x}{(2 y - 1)}

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