Y - fx is differentiable function and gx-fx-x2 If y-gx has local maxima at x- 12 but the absolute maximum exists at some other points- then a minimum number of a solution of gx-0 is

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Standard XII

Mathematics

Quadratic Equation

y = fx is dif...

Question

$y = f (x)$ is differentiable function and $g (x) = f (x - x^{2})$ If $y = g (x)$ has local maxima at x= $\frac{1}{2}$ but the absolute maximum exists at some other points, then a minimum number of a solution of $g (x) = 0$ is

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Solution

Hence minimum number of solution of $g (x) = 0$ is $3.$

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y=f(x) is differentiable function and g(x)=f(x−x2) If y=g(x) has local maxima at x=12 but the absolute maximum exists at some other points, then a minimum number of a solution of g(x)=0 is

Hence minimum number of solution of g(x)=0 is 3.

$y = f (x)$ is differentiable function and $g (x) = f (x - x^{2})$ If $y = g (x)$ has local maxima at x= $\frac{1}{2}$ but the absolute maximum exists at some other points, then a minimum number of a solution of $g (x) = 0$ is

Hence minimum number of solution of $g (x) = 0$ is $3.$