You are given the solution of lead nitrate. In order to obtain a yellow precipitate you should mix with it a solution of :

potassium chloride

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potassium nitride

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potassium sulphide

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potassium iodide

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Solution

The correct option is D potassium iodide
Yellow precipitate is due to the formation of $P b I_{2}$ which forms when lead nitrate is mixed with potassium iodide.

$P b (N O_{3})_{2} (a q) + 2 K I (a q) \to P b I_{2} (s) + 2 K N O_{3} (a q)$

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Similar questions

Q. You are given the solution of lead nitrate. In order to obtain a yellow precipitate you should mix with it a solution of:
(a) potassium chloride
(b) potassium nitride
(c) potassium sulphide
(d) potassium iodide

Q. Assertion :"A golden yellow precipitate of lead iodide is formed when colourless lead nitrate solution is mixed with colourless solution of potassium iodide." So, it is a chemical change Reason: Formation of new products in the reaction with the precipitate indicates a chemical change

Lead nitrate reacts with potassium iodide to form a yellow precipitate of.

Q. In the double displacement reaction between aqueous potassium iodide and aqueous lead nitrate solution, a yellow precipitate of lead iodide is obtained. While performing the activity if lead nitrate is not available, which of the following can be used in the place of lead nitrate?

$P b (N O_{3})_{2} (a q) + 2 K C l (a q) \to 2 K N O_{3} (a q) + P b C l_{2} (s)$

When lead nitrate solution is mixed with potassium chloride solution, a precipitate of lead chloride and potassium nitrate solution are formed. This type of reaction is called _________________.

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You are given the solution of lead nitrate. In order to obtain a yellow precipitate you should mix with it a solution of :

The correct option is D potassium iodideYellow precipitate is due to the formation of PbI2 which forms when lead nitrate is mixed with potassium iodide.Pb(NO3)2(aq)+2KI(aq)→PbI2(s)+2KNO3(aq)

The correct option is D potassium iodide
Yellow precipitate is due to the formation of $P b I_{2}$ which forms when lead nitrate is mixed with potassium iodide.

$P b (N O_{3})_{2} (a q) + 2 K I (a q) \to P b I_{2} (s) + 2 K N O_{3} (a q)$