Question

You stumble upon the "coordinates" of a common element. The "coordinate" is actually the electronic configuration given as $\left[Ne\right]3s^{2}3p^3$.
What element corresponds to this location?

• A. $Si$
• B. $P$
• C. $S$
• D. $Cl$

Answer 1

Answer: (B)

$P$

The number of electrons of this element $=\left[10\right]+2+3$

$=15$ ($\left[10\right]$ for $\left[Ne\right]$)

Thus atomic number of this element is $15$,i.e., the element is Phosphorous.