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Byju's Answer
Standard XII
Mathematics
Complex Numbers
z1 and z 2 ...
Question
z
1
and
z
2
are two distinct points in an Argand plane. If
a
|
z
1
|
=
b
|
z
2
|
(where
a
,
b
∈
R
)
,
then the point
(
a
z
1
/
b
z
2
)
+
(
b
z
2
/
a
z
1
)
is a point on the
A
line segment
[
−
2
,
2
]
of the real axis
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B
line segment
[
−
2
,
2
]
of the imaginaryaxis
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C
unit circle
|
Z
|
=
1
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D
the line with
a
r
g
z
=
tan
−
1
2
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Solution
The correct option is
A
line segment
[
−
2
,
2
]
of the real axis
Let
z
1
=
|
z
1
|
e
i
θ
z
2
=
|
z
2
|
e
i
(
θ
+
α
)
a
z
1
b
z
2
+
b
z
2
a
z
1
⟹
a
|
z
1
|
e
i
θ
b
|
z
2
|
e
i
(
θ
+
α
)
b
|
z
2
|
e
i
(
θ
+
α
)
a
|
z
1
|
e
i
(
θ
)
(
a
|
z
1
|
=
b
|
z
2
|
)
⟹
e
−
i
α
+
e
i
α
⟹
Real no. on
[
−
2
,
2
]
segments.
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0
Similar questions
Q.
If
z
1
and
z
2
are two distinct points in an argand plane such that
a
|
z
1
|
=
b
|
z
2
|
(where
a
,
b
∈
R
)
, then the point
(
a
z
1
b
z
2
+
b
z
2
a
z
1
)
will always lie on the
Q.
|
z
1
|
and
|
z
2
|
are two distinct points in an Argand plane. If
a
|
z
1
|
=
b
|
z
2
|
(where
a
,
b
∈
R
), then the point
(
a
z
1
/
b
z
2
)
+
(
b
z
2
/
a
z
1
)
is a point on the
Q.
z
1
and
z
2
are two distinct points in an Argand plane. If
a
|
z
1
|
=
b
|
z
2
|
(where a, b
ϵ
R), then the point
(
a
z
1
/
b
z
2
)
+
(
b
z
2
/
a
z
1
)
is a point on the
Q.
Assertion :Let
z
1
&
z
2
are two distinct points in the argand plane such that
a
|
z
1
|
=
b
|
z
2
|
where
a
,
b
ϵ
R
.
The expression
a
z
1
b
z
2
+
b
z
2
a
z
1
is a point on the line segment [-2, 2] of the real axis. Reason: When arg
(
z
1
)
=
θ
& arg
(
z
2
)
=
θ
+
α
, then
a
z
1
b
z
2
+
b
z
2
a
z
1
=
e
i
α
+
e
−
i
α
=
2
c
o
s
α
Q.
Z
1
≠
Z
2
are two points in an argand plane. If
a
|
Z
1
|
=
b
|
Z
1
|
Prove that
a
Z
1
−
b
Z
2
a
Z
1
+
b
Z
2
is purely imaginary.
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