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Question

Zeroes of the polynomial x24x21 are :

A
3 and 7
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B
3 and 7
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C
3 and 7
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D
3 and 7
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Solution

The correct option is B 3 and 7
We have, a formula for solving quadratic equation ax2+bx+c=0 is
x=b±b24ac2a.

Zeroes or roots of the polynomial x24x21 are:

=(4)±(4)24×1(21)2(1)

=4±16+842

=4+102 and 4102

=7 and 3.

So, B is correct.

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