Zn2- aq - 2e - Zns- This is

2+Zn_eq+2e^ →0Zn_s reduction. ...

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Redox Reactions

Zn2+ aq + 2e ...

Question

$Z n^{2 +} (a q) + 2 e \to Z n (s)$ . This is

Oxidation

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Reduction

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Redox reaction

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None of these

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Z n^{2 +} (a q) + 2 e \to Z n (s)

{Z n}^{2 +} (a q) + {2 e}^{-} \to Z n (s)

0.76 V

Z n^{2 +} (a q) + 2 e^{-} \to Z n (s)

(K_{f})

Z n^{2 +} (a q) + 4 O H^{-} (a q) ⇌ Z n (O H)_{4}^{2 -} (a q)

p \times 10^{q},

Z n^{2 +} (a q) + 2 e^{-} \to Z n (s); E^{0} = - 0.76 V

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2.303 \frac{R T}{F} = 0.06

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