Zn+Hcl-ZnCl2+H2
1. how many molecules of hydrogen are produced from the reaction of three moles of zinc with an excess of hydrochloric acid?
2. What would be the volume of the same number of carbon dioxide molecules at stp
3. State the law used to answer the above question.

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Solution

Balanced reaction = Zn + 2HCl ---> ZnCl₂ + H2

(1) 3 moles of Hydrogen are produced

(2)22.4 x 3 = 67.2 litres

(3) Law of Definite Proportion

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Zn+Hcl-ZnCl2+H2 1. how many molecules of hydrogen are produced from the reaction of three moles of zinc with an excess of hydrochloric acid? 2. What would be the volume of the same number of carbon dioxide molecules at stp 3. State the law used to answer the above question.

Balanced reaction = Zn + 2HCl ---> ZnCl2 + H2 (1) 3 moles of Hydrogen are produced (2)22.4 x 3 = 67.2 litres (3) Law of Definite Proportion

Zn+Hcl-ZnCl2+H2
1. how many molecules of hydrogen are produced from the reaction of three moles of zinc with an excess of hydrochloric acid?
2. What would be the volume of the same number of carbon dioxide molecules at stp
3. State the law used to answer the above question.

Balanced reaction = Zn + 2HCl ---> ZnCl₂ + H2

(1) 3 moles of Hydrogen are produced

(2)22.4 x 3 = 67.2 litres

(3) Law of Definite Proportion