Question

Zn is the oxidant in the following reaction

$Zn\left(s\right)+\frac{1}{2}{O}_2⟶ZnO\left(s\right)$

• A. True
• B. False

Answer 1

The correct option is B

False

We know that an oxidizing agent or oxidant is a substance which supplies Oxygen or any other electronegative element or removes hydrogen or any other electropositive element. Alternatively, an oxidizing agent or oxidant is that substance which itself undergoes reduction in a chemical reaction.

Now, first we have to check the oxidation numbers of $Zn$ and $O$. Oxidation implies an increase in oxidation state.

Let's check,

$\stackrel{0}{Z}n\left(s\right)+\frac{1}{2}{\stackrel{0}{O}}_2⟶\stackrel{+2}{Z}n\stackrel{-2}{O}$

Clearly, Zn is oxidised, so it will be a reductant or reducing agent.