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Nernst Equation

Zn | Zn2+ aq ...

Question

$Z n | Z n^{2 +} (a q) | | C u^{2 +} (a q) | C u$ . $E^{o}$ for $C u$ and $Z n$ are $0.35$ and $- 0.76$ respectively:
Find EMF of cell (nearest integer) if $Z n^{2 +}$ and $C u^{2 +}$ are 1 M each.

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Solution

$E_{c e l l}^{0} = E_{C u^{2 +} | C u}^{0} - E_{Z n^{2 +} | Z n}^{0}$

$E_{c e l l}^{0} = 0.35 V - (- 0.76 V)$

$E_{c e l l}^{0} = 1.11 V$

Now,
$E_{c e l l} = E_{c e l l}^{0} - \frac{0.0591}{n} l o g \frac{[Z n^{2 +}]}{[C u^{2 +}]}$

$E_{c e l l} = 1.11 V - \frac{0.0591}{2} l o g \frac{1}{1}$

$E_{c e l l} = 1.11 V - 0$

$E_{c e l l} = 1.11 V$

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Z n | Z n^{2 +} (a q) | | C u^{2 +} (a q) | C u

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For cell reaction, $Z n + C u^{2 +} \to Z n^{2 +} + C u,$ cell representation is

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