214.2 g of sugar syrup contains 34.2 g of sugar. Calculate (i) molarity of the solution (ii) mole fraction of sugar in the syrup.

Given that mass of sugar = 34.2 g

No. of moles of sugar = 34.2/molecular mass = 34.2/342 = 0.1

Mass of water = (214.2-34.2)=180g= 180/1000Kg

No. of moles of water = 180/18 = 10 mole

Molarity = No.ofmolesofsugar/Mass of water in kg

0.1/180 × 1000 = 0.555M

Thus, the molarity of sugar is 0.555 M

Total number of moles = 10.0 + 0.1 = 10.1

Mole fraction of sugar = No.ofmolesofsugar/Total number of moles

0.1/10.1 = 0.0099

Thus mole fraction of sugar syrup is 0.0099

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