Question

$2{\mathrm{NaNO}}_3+10\mathrm{Na}\to \mathrm{\_\_\_\_\_\_\_\_\_\_\_\_\_\_}+{\mathrm{N}}_2$

$2{\mathrm{NaNO}}_2+6\mathrm{Na}\to \mathrm{\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_}+{\mathrm{N}}_2$

The Product Obtained is as Follows:

Answer 1

These two reactions are used for the synthesis of Nitrogen from Sodium nitrate with the help of Sodium metal.

1. When Sodium nitrate is treated with Sodium metal, it will lead to the formation of Nitrogen and Sodium oxide.

$\underset{\mathrm{Sodium}\mathrm{nitrate}}{2{\mathrm{NaNO}}_3}+\underset{\mathrm{Sodium}}{10\mathrm{Na}}\to \underset{\mathrm{Sodium}\mathrm{oxide}}{6{\mathrm{Na}}_2\mathrm{O}}+\underset{\mathrm{Nitrogen}}{{\mathrm{N}}_2}$

2. When Sodium nitrite is treated with Sodium metal, it will lead to the formation of Nitrogen and Sodium oxide.

$\underset{\mathrm{Sodium}\mathrm{nitrite}}{2{\mathrm{NaNO}}_2}+\underset{\mathrm{Sodium}}{6\mathrm{Na}}\to \underset{\mathrm{Sodium}\mathrm{oxide}}{4{\mathrm{Na}}_2\mathrm{O}}+\underset{\mathrm{Nitrogen}}{{\mathrm{N}}_2}$

Hence, the Product Obtained is Sodium oxide(Na₂O).