Question

A balloon is filled with hydrogen at room temperature, it will burst if pressure exceeds $0.2bar$. If at $1bar$ pressure the gas occupies $2.27L$ volume, up to what volume can the balloon be expanded?

Answer 1

Step 1: Given Data

$P_1=1bar$

$V_1=2.27L$

$P_2=0.2bar$

Step 2: Formula Used

According to Boyle’s law, we know that
$P_1{V}_1=P_2{V}_2$

$\Rightarrow V_2=\frac{P_1{V}_1}{P_2}$

Step 3: Calculate the required volume

Upon substituting the values we get

$V_2=\frac{1\times 2.27}{0.2}$

$=11.35L$

Hence, the maximum volume to which the balloon can be expanded is $11.35L$.