Question

A compound has the molecular formula X₄O₆, if 10 G of X₄O₆ has 5.72 G Of X, then find the atomic mass of X?

Answer 1

Step 1: Given

The molecular weight of the compound

${\mathrm{X}}_4{\mathrm{O}}_6$

Step 2: Deriving expression

Expressing the above formula = $4\times X+6\times 16$

= $4\mathrm{X}+96$

Since ($4X+96$)gm of ${\mathrm{X}}_4{\mathrm{O}}_6$ contains $\mathrm{X}=4\mathrm{a}$gm

Therefore, $10\mathrm{gm}$of ${\mathrm{X}}_4{\mathrm{O}}_6$ will contain,

$X=\frac{4\mathrm{a}\times 10}{4\mathrm{a}+96}$

Step 3: Calculation of atomic mass

Putting suitable values in the above formula and calculating, we get

$$\begin{gathered} 5.72=\frac{4\mathrm{a}\times 10}{4\mathrm{a}+96} \\ 22.88\mathrm{a}+549.12=4\mathrm{a} \\ 17.12\mathrm{a}=549.12 \\ \mathrm{a}=32.07\mathrm{amu} \end{gathered}$$

Therefore, the atomic mass of X is $32.07$amu.