Question

A Cyclist Turns Around A Curve At $15Km/hr$ If He Turns At Double The Speed The Tendency To Overturn Is :

Answer 1

Formula :

We know centrifugal force , $F=\frac{m{v}^2}{r}$

where

$v=$velocity of the object

$m=$ mass of the object

$r=$turning radius

As the mass and turning radius does not change in this case, we consider them as constant.

Thus we can say that

Centrifugal force, $\mathrm{F}=\mathrm{\alpha }{\mathrm{v}}^2(\mathrm{where}\mathrm{a}=\frac{\mathrm{m}}{\mathrm{r}}=\mathrm{constant})$

Now, as per the question, if the velocity of the cyclist is doubled, then its tendency to overturn will be increased by four times.

Hence, If a cyclist turns around a curve at $15\mathrm{Km}/\mathrm{hr}$ and if he turns at double the speed , the tendency to overturn will be increased by four times.