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Question

A galvanometer has a resistance of 3663ω. A shunt S is connected across it such that 134 of the total current passes through the galvanometer. The value of the shunt is


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Solution

Step 1: Given data

A galvanometer has a resistance of G=3663ω.

A shunt S is connected across it such that 134 of the total current passes through the galvanometer.

Step 2: Formula used

A shunt S is connected in parallel with a galvanometer with resistance G , then we know that the current in the circuit gets divided. If i is the total current in the circuit and ig is the current in the galvanometer, then the current flowing through the shunt resistance is given as is=iig

SG=igi-ig

Step 3: Calculating the value of the shunt

Given that the ig=i34
Since the voltage in both circuit are equal, we also know from the ohms law that V=IR.

Applying the same, we SG=igiig
Also, given that the G=3663ω

Substituting the values, we get, S=i34ii34×G

S=G33=366333=111ω

Hence, the value of the shunt is 111ω.


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