A Grinding Wheel Attained A Velocity Of 20 Rad/Sec In 5 Sec Starting From Rest. Find The Number Of Revolutions Made By The Wheel.

The angular acceleration is given as:

\( a = \frac{\omega _{f} – W _{i}}{t} \) \( \Rightarrow \frac{20 – 0}{5} \) \( \Rightarrow 4 rad/s^{2} \)

By using

\( \Theta = \omega _{i}t + \frac{1}{2}at^{2} \) \( \Rightarrow \Theta = 0 + 0.5 * 4 * 25 \) \( \Rightarrow \Theta = 50 rad \)

The number of revolutions is

\( n = \frac{50}{2\Pi} \) \( \Rightarrow \frac{25}{2\Pi} \)

Therefore, the number of revolutions is \( \frac{25}{2\Pi} \)

Explore more such questions and answers at BYJU’S.

Was this answer helpful?

 
   

0 (0)

(0)
(1)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question